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72x^2-96x+24=0
a = 72; b = -96; c = +24;
Δ = b2-4ac
Δ = -962-4·72·24
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-48}{2*72}=\frac{48}{144} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+48}{2*72}=\frac{144}{144} =1 $
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